This Test: 200 pts possible This Question: 20 pts common oolds in a test of the

Question

This Test: 200 pts possible This Question: 20 pts common oolds in a test of the effctiveness of echinaces, 43 of the 48 subjects treated with chinces developed iinwinus inections in a placebo group. 77 of the 32 sujets hinovirus inlections Use a 0.0 signficance level to Seat the claim that echinace as an efect on hinovinus infections Complete parts (a) trough (e) below a Test the dlaire using a hypothesis hypothesis tes Round to twe decimal places as meeded) dentily the Pal Round to three decimal giaces as needed) Round to thee decimal places s needed) Click to select your anwer 3 cops lock

Explanation / Answer

Question a)

Hypothesis

Answer: Option A

Test Statistics:

z = (p1^ - p2^) / SE (p1-p2)

SE (p1-p2) = sqrt (P*Q*((1/n1)+(1/n2))

P = (x1+x2)/(n1+n2)

x1 = 43

n1 = 48

x2 = 77

n2 = 92

p1^ = 0.895833

p2^ = 0.836957

P = 0.857143

Q = 0.142857

SE (p1-p2) = 0.0623

z = (0.895833-0.836957)/0.0623

z = 0.94

P-value = 0.174

The p-value is greater than the significance level of a = 0.05 so fail to reject the null hypothesis. There is not sufficient evidence to support the claim that ....

Question b)

(p1^ -p2^) (-/+) SE (p1-p2)

(0.895833 - 0.836957) (-/+) (1.96 * 0.0623)

-0.056 < (p1-p2) < 0.174

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