A previous poll found that \"433 of the 1548 randomly-selected adults questioned

Question

A previous poll found that "433 of the 1548 randomly-selected adults questioned felt that unemployment compensation should be extended an additional six months while the country is in its current economic downturn." You want to determine if the same proportion of adults feel this way today, so you will conduct your own survey, what sample size is needed so that the 95% confidence interval will have a margin of error of no more than 2%? (Keep four decimal places or you also have the option to round off your answer.)

Explanation / Answer

p = 433/1548

standard error = sqrt( 433/1548 * 1115/1548 * 1/n)

margin of error = 0.02

1.96 * sqrt( 433/1548 * 1115/1548 * 1/n) = 0.02

=>

n = 1934.96 = 1935

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