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Fred G. Hire is the manager of human resources at Crescent Tool and Die Inc. As

ID: 3269058 • Letter: F

Question

Fred G. Hire is the manager of human resources at Crescent Tool and Die Inc. As part of his yearly report to the CEO, he is required to present an analysis of the salaried employees. Because there are over 1,000 employees, he does not have the staff to gather information on each salaried employee, so he selects a random sample of 30. For each employee, he records monthly salary; service at Crescent, in months; gender (1 = male, 0 = female); and whether the employee has a technical or clerical job. Those working technical jobs are coded 1, and those who are clerical 0.

A. Using salary as the dependent variable and the other four variables as independent variables, write out the regression equation.

B. What is the value of R2? Comment on this value.

C. What is the label that you would give the variable, gender?

D. Conduct a global test of hypothesis to determine whether any of the independent variables are different from 0.

E. Conduct an individual test for Age to determine whether it can be dropped from the equation.

F. Rerun the regression equation, using only the independent variables that are significant. Write out your new regression equation. Hint: You may need to rearrange some of your variables in Excel. You can insert a new column and then cut and paste.

G. Using the following information: Length of Service = 115, Age 40, Gender 1, and Job 1; estimate the employee’s salary. Remember, you will not be using all of the variables!

Employee Salary Service Age Gender Job 1 $      1,769.0 93 42 1 0 2 $      1,740.0 104 33 1 0 3 $      1,941.0 104 42 1 1 4 $      2,367.0 126 57 1 1 5 $      2,467.0 98 30 1 1 6 $      1,640.0 99 49 1 1 7 $      1,756.0 94 35 1 0 8 $      1,706.0 96 46 0 1 9 $      1,767.0 124 56 0 0 10 $      1,200.0 73 23 0 1 11 $      1,706.0 110 67 0 1 12 $      1,985.0 90 36 0 1 13 $      1,555.0 104 53 0 0 14 $      1,749.0 81 29 0 0 15 $      2,056.0 106 45 1 0 16 $      1,729.0 113 55 0 1 17 $      2,186.0 129 46 1 1 18 $      1,858.0 97 39 0 1 19 $      1,819.0 101 43 1 1 20 $      1,350.0 91 35 1 1 21 $      2,030.0 100 40 1 0 22 $      2,550.0 123 59 1 0 23 $      1,544.0 88 30 0 0 24 $      1,766.0 117 60 1 1 25 $      1,937.0 107 45 1 1 26 $      1,691.0 105 32 0 1 27 $      1,623.0 86 33 0 0 28 $      1,791.0 131 56 0 1 29 $      2,001.0 95 30 1 1 30 $      1,874.0 98 47 1 0

Explanation / Answer

Answer:

Regression Analysis

0.433

Adjusted R²

0.342

n

30

R

0.658

k

4

Std. Error

236.529

Dep. Var.

Salary

ANOVA table

Source

SS

df

MS

F

p-value

Regression

1,066,830.3889

4  

266,707.5972

4.77

.0054

Residual

1,398,650.9778

25  

55,946.0391

Total

2,465,481.3667

29  

Regression output

confidence interval

variables

coefficients

std. error

   t (df=25)

p-value

95% lower

95% upper

Intercept

651.8575

345.3017

1.888

.0707

-59.3046

1,363.0197

Service

13.4219

5.1253

2.619

.0148

2.8662

23.9776

Age

-6.7102

6.3494

-1.057

.3007

-19.7870

6.3667

Gender. Male

205.6455

90.2657

2.278

.0315

19.7399

391.5512

Job

-33.4530

89.5474

-0.374

.7119

-217.8794

150.9734

Salary = 651.8575+13.4219* Service -6.7102* Age +205.6455* Gender. Male -33.4530* Job

B. What is the value of R2? Comment on this value.

R2 =0.433

43.3% of variance in alary is explained by the regression model.

C. What is the label that you would give the variable, gender?

Gender. male

D. Conduct a global test of hypothesis to determine whether any of the independent variables are different from 0.

Calculated F=4.77, P=0.0054 which is < 0.05 level of significance.

We conclude that atleast one of the independent variables are different from 0.

E. Conduct an individual test for Age to determine whether it can be dropped from the equation.

Calculated t= -1.057, P=0.3007which is > 0.05 level of significance. Age is not significant

Age can be dropped from the equation.

F. Rerun the regression equation, using only the independent variables that are significant. Write out your new regression equation. Hint: You may need to rearrange some of your variables in Excel. You can insert a new column and then cut and paste.

Regression Analysis

0.405

Adjusted R²

0.361

n

30

R

0.636

k

2

Std. Error

233.071

Dep. Var.

Salary

ANOVA table

Source

SS

df

MS

F

p-value

Regression

998,778.6683

2  

499,389.3342

9.19

.0009

Residual

1,466,702.6983

27  

54,322.3222

Total

2,465,481.3667

29  

Regression output

confidence interval

variables

coefficients

std. error

   t (df=27)

p-value

95% lower

95% upper

Intercept

784.1862

316.8193

2.475

.0199

134.1267

1,434.2458

Service

9.0212

3.1063

2.904

.0073

2.6476

15.3949

Gender. Male

224.4063

87.3520

2.569

.0160

45.1748

403.6379

Salary = 784.1862 +9.0212 * Service +224.4063 * Gender. Male

G. Using the following information: Length of Service = 115, Age 40, Gender 1, and Job 1; estimate the employee’s salary.

Estimated Salary = 784.1862 +9.0212 * 115 +224.4063 * 1

=$2046.03

Regression Analysis

0.433

Adjusted R²

0.342

n

30

R

0.658

k

4

Std. Error

236.529

Dep. Var.

Salary

ANOVA table

Source

SS

df

MS

F

p-value

Regression

1,066,830.3889

4  

266,707.5972

4.77

.0054

Residual

1,398,650.9778

25  

55,946.0391

Total

2,465,481.3667

29  

Regression output

confidence interval

variables

coefficients

std. error

   t (df=25)

p-value

95% lower

95% upper

Intercept

651.8575

345.3017

1.888

.0707

-59.3046

1,363.0197

Service

13.4219

5.1253

2.619

.0148

2.8662

23.9776

Age

-6.7102

6.3494

-1.057

.3007

-19.7870

6.3667

Gender. Male

205.6455

90.2657

2.278

.0315

19.7399

391.5512

Job

-33.4530

89.5474

-0.374

.7119

-217.8794

150.9734

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