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Data was collected from 40 employees to develop a regression model to predict th

ID: 3268492 • Letter: D

Question

Data was collected from 40 employees to develop a regression model to predict the employee’s annual salary using their years with the company (Years), their starting salary (Starting), and their Gender (Male = 0, Female = 1). The results from Excel regression analysis are shown below:

SUMMARY OUTPUT

Regression Statistics

Multiple R

0.718714957

R Square

0.516551189

Standard Error

10615.63461

Observations

40

ANOVA

df

SS

MS

F

Significance F

Regression

3

4334682510

1444894170

12.82165585

7.48476E-06

Residual

36

4056901131

112691698.1

Total

39

8391583641

Coefficients

Standard Error

t Stat

P-value

Intercept

27946.57894

4832.438706

5.783121245

1.35464E-06

Years

1665.251558

425.0829092

3.917474737

0.000383313

Starting

0.266374185

0.12610443

2.112330112

0.041661598

Gender

-3285.541043

5617.145392

-0.584912943

0.56225464

                  In testing the null hypothesis that the regression equation is not significant at the 0.05 level, what is the appropriate conclusion?

SUMMARY OUTPUT

Regression Statistics

Multiple R

0.718714957

R Square

0.516551189

Standard Error

10615.63461

Observations

40

ANOVA

df

SS

MS

F

Significance F

Regression

3

4334682510

1444894170

12.82165585

7.48476E-06

Residual

36

4056901131

112691698.1

Total

39

8391583641

Coefficients

Standard Error

t Stat

P-value

Intercept

27946.57894

4832.438706

5.783121245

1.35464E-06

Years

1665.251558

425.0829092

3.917474737

0.000383313

Starting

0.266374185

0.12610443

2.112330112

0.041661598

Gender

-3285.541043

5617.145392

-0.584912943

0.56225464

Explanation / Answer

Here the test-statistic for testing the null hypothesis that the regression equation is not significant again the alternative

that it is significant is given by, F = MSReg / MSTotal = 1444894170 / 112691698.1 = 12.82165585.

The p-value of the test = P(F > 12.82165585) , where F ~ F-distribution with (3,36) d.f.

= 7.48476E-06

Since , p-value = 7.48476E-06 < level of signficance = 0.05, we reject our null hypothesis. Hence, we conclude that the regression equation is significant. (Ans).