needing help with 2, 4, 6, 8 and 12 Hormula for the standard error of the mean m

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needing help with 2, 4, 6, 8 and 12

Hormula for the standard error of the mean mial distribution Review Exercises limits of the middle 50% of individ expenditures 1. Find the area under the standard normal distribution 6. Salaries for Actuaries The average a. Between z = 0 and z 1 .95 h Between z = 0 and z = 0.37 c. Between= 1.32 and z = 1.82 d. Between z =-1.05 and z = 2.05 graduates entering the actuarial field salaries are normally distributed with a deviation of $5000, find theobabilityt a. An individual graduate will have a sal Between z =-0.03 and z 0.53 A group of nine graduates will have a 2. Find the area under the standard normal distribution for each a. Between z 110 and-=-1 .80 b. To the right of z 1.99 c. To the right of -1.36 d. To the left of z=_209 e. To the left of z 1.68 7. Commuter Train Passengers On a cerlain nun commuter train, the average number of and the standard deviation is 22. Assume t normally distributed. If the train makes th probability that the number of passengers will be run a. Between 476 and 500 passengers b. Less than 450 passengers c. More than 510 passengers 3. Using the standard normal distribution, find each a. POz

Explanation / Answer

1)

b) P(0 <z<0.37) = 0.1443

c) P(1.32 < Z< 1.82 ) = 0.059

d) P(-1.05 <Z< 2.05) = 0.833

2)

you have to look in normal table locate z

then P(Z< z) can be found

if z = -1.36

then look for -1.3 in row and 6 in the column

and then corresponding value is P(Z < -1.36)

P(Z > z) = 1 - P(Z <z)

a) P(-1.8 <Z< 1.1) = P(Z< 1.1) - P(Z < -1.8) = 0.8284

b) P(Z > 1.99) = 0.0233

c) P(Z >-1.36) = 0.9131

d)P(Z < -2.09) = 0.0183

e) p(Z< 1.68) = 0.9535

similarly Q4 can be done . Pot rest questions again

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