I need help answering 2, 4, 6, 8 and 16 Formula for finding a value c percentile
ID: 3268468 • Letter: I
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I need help answering 2, 4, 6, 8 and 16
Formula for finding a value c percentile: Expression for Chebyshev's theorem: The values from a data set that will fall within k standard proportion of I1 100 deviations of the mean will be at least Formula for interquartile range: IQR = Q3-Q1 where k is a number greater than 1 Review Exercises Score 478-504 505-531 532-558 559-585 586-612 Source: World Almana. Frequency Section 3-1 4 1. Net Worth of Wealthy People The net worth (in billions of dollars) of a sample of the richest people in the United States is shown. Find the mean, median mode, and midrange for the data. 59 52 28 26 19 19 18 17 17 17 Source: Forbes magazine. 5. Households of Four Television Networks A survey showed the number of viewers and nuthe of households of four television networks Fats average number of viewers, using the weightedl 2. Shark Attacks The number of shark attacks and deaths over a recent 5-year period is shown. Find the mean, median, mode, and midrange for the data. Attacks 71 64 61 65 57 Deaths 1 4 4 7 4 mean Households Viewers (in millions) 1.6 Source: Nielsen Media Research. 1.4 0.8 3 0.8 04 3. Battery Lives Twelve batteries were tested to see how many hours they would last. The frequency distribution is shown here. 6. Investment Earnings An investor calculatol t percentages of each of three stock investments wi payoffs as shown. Find the average payoff l'se t weighted mean. Stock Hours Frequency 1-3 4-6 7-9 10-12 13-15 Find the mean and modal class 4 Percent 30 50 20 Pavoff S10,000 3,000 1,000 4. SAT Scores The mean SAT math scores for selected states are represented. Find the mean class and modal class 3-70Explanation / Answer
Dear student, please post one question at a time. Thanks.
Solution of question 2:
Attacks:
mean= 63.6
median=64
mode=0
midrange=(71-57)/2=7
variance =26.8
standard deviation= 5.176872
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Deaths:
mean=4
median=4
mode=4
midrange=(7-1)/2=3
variance = 4.5
standard deviation= 2.121320
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