1 Your company manufactures 25,000 LCD TV Screens per month for world wide distr
ID: 326729 • Letter: 1
Question
1 Your company manufactures 25,000 LCD TV Screens per month for world wide distribution. You randomly sample 800 units each week, 2 looking for three characteristics. During a rcent week, 4 defects were found for one characteristic, two defects were found for another 3 characteristic and one defect was found for the third characteristic. If these defect counts are representative of the population, what is the overall sigma level for this process? 4 What is the sigma level for the characteristic that showed four defects?Explanation / Answer
Population=25000/4=
Sample size=800
Total defects found = 4+2+1=7
Process Yield= ((#opportunities-#defects)/#opportunities)*100
Process Yield=((800-7)/800)*100=99.125%
From the table used to convert Process Yield to Sigma value- we get that 99.125% approximately is equivalent to an yield of 3.875.
For characteristic that showed 4 defects:
Process Yield= ((800-4)/800)*100=99.5%
Sigma corresponding to this Yield level is 4.125 approximately.
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