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Test: Test (Chapters 22, 24, and 25) Submit T This Question: 1 pt 1of11(0complet

ID: 3267007 • Letter: T

Question

Test: Test (Chapters 22, 24, and 25) Submit T This Question: 1 pt 1of11(0complete) This Test: 11 pts poss A study examined parental i oward smoking. These students were questioned again two years later to see if ndicated that their parents disapproved of kids smoking. about smoking. 17 became smokers. Do these data hrough f OD. Yes, all of the assumptions and conditions are satisfed 0E. No, because the independent groups assumption is not satisfied nfluence on teenagers' decisions to smoke. A group of students who had never smoked were quessioned about their parents' atitudes The researchers found that, among the 263 students wha 40 had become established smokers. Among the 49 students who initially said their parents were lenient provideong evidence that parental attude infuences teenagers' decisions about smoking? Complete parts a d) Test the hypothesis and stake your condlusion Determine the test statistic Round to twro decimal places as needed) Find the P value P.Rund to four decrnal places as needed ) State your concdusion. Use a significance level of a -0.05. Choose the correct answer below O A. Do not neject the null hypotsis. There is sufficient evidence that parental aftitule infuences teenagers' decisions about smoking There is not sulficient evidence that parental atihude infiuences teenagens' decisions about smoking O B. Do not reject the null hypothesis. not suicient teenagens decisions about smoking Do. Reject the null ypothesis There is not sufficent videncathat parental athude infuencoss tenagers decisions about smoking Cick to select your answers) Week 7 (July 31-Aug. ) 3 5 8 WE

Explanation / Answer

Solution:-

State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.

Null hypothesis: P1 = P2

Alternative hypothesis: P1 P2

Note that these hypotheses constitute a two-tailed test. The null hypothesis will be rejected if the proportion from population 1 is too big or if it is too small.

Formulate an analysis plan. For this analysis, the significance level is 0.05. The test method is a two-proportion z-test.

Analyze sample data. Using sample data, we calculate the pooled sample proportion (p) and the standard error (SE). Using those measures, we compute the z-score test statistic (z).

p = (p1 * n1 + p2 * n2) / (n1 + n2)

p = 0.183

SE = sqrt{ p * ( 1 - p ) * [ (1/n1) + (1/n2) ] }

SE = 0.06018

z = (p1 - p2) / SE

z = - 3.238

where p1 is the sample proportion in sample 1, where p2 is the sample proportion in sample 2, n1 is the size of sample 1, and n2 is the size of sample 2.

Since we have a two-tailed test, the P-value is the probability that the z-score is less than - 3.24 or greater than 3.24.

Thus, the P-value = 0.0012

Interpret results. Since the P-value (0.0012) is less than the significance level (0.05), we cannot accept the null hypothesis.

From the above test we have sufficient evidence in the favor of the claim that parental attitude influences teenager's decision about smoking.

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