The USL = 5.25 and the USL = 1.75 Compute the process capability and discuss its
ID: 3265341 • Letter: T
Question
The USL = 5.25 and the USL = 1.75
Compute the process capability and discuss its meaning in managerial terms.
3.4241
3.1500
4.2700
4.7500
3.7712
3.7222
3.9693
4.2100
3.7372
2.9244
2.7614
4.0400
3.7600
3.3800
3.9052
3.8841
3.1841
3.0389
4.0814
3.6797
3.4380
3.5000
3.2600
4.1600
4.5165
3.5836
3.0613
2.6684
3.2231
3.2930
2.7929
3.9200
3.2925
2.9400
3.4145
3.1548
3.1951
3.3722
3.9073
3.2287
Data cont’
3.6383
3.4235
4.2948
3.4161
4.1828
3.9349
3.2861
3.5300
2.8000
4.5715
2.7606
4.2848
2.3321
3.2983
4.2396
3.3058
4.5357
3.1600
3.9700
3.4684
3.2057
4.0046
2.8023
3.2538
3.1492
3.7743
2.9748
3.7500
2.7700
4.0084
3.9761
3.5487
3.2834
4.0892
3.7022
3.4609
3.6780
2.9600
2.8400
3.5241
Data cont’
3.6063
2.9995
3.4100
3.1500
3.2000
3.4041
3.7447
3.2900
3.2100
4.0000
4.4060
3.3615
4.2400
3.3100
4.5400
3.1594
2.8544
3.5300
3.8200
2.8000
3.4241
3.1500
4.2700
4.7500
3.7712
3.7222
3.9693
4.2100
3.7372
2.9244
2.7614
4.0400
3.7600
3.3800
3.9052
3.8841
3.1841
3.0389
4.0814
3.6797
3.4380
3.5000
3.2600
4.1600
4.5165
3.5836
3.0613
2.6684
3.2231
3.2930
2.7929
3.9200
3.2925
2.9400
3.4145
3.1548
3.1951
3.3722
3.9073
3.2287
Explanation / Answer
The given data has average =3.528
standard deviation of given data = 0.504
so Process Capability Cp = (USL - LSL)/ 6 sigma = (5.25 - 1.75) / 6 * 0.504 =1.157
or Cpm = min [ (USL - xbar )/ 3s , (xbar - LSL)/ 3s ]
(USL - xbar )/ 3s = (5.25 - 3.528)/ (3* 0.504) = 1.139
(xbar - LSL) / 3s = (3.528 - 1.75)/ (3* 0.504) = 1.176
so Cpm = 1.139 or 1.14
Process capability compares the output of an in-control process to the specification limits by using capability indices. The comparison is made by forming the ratio of the spread between the process specifications (the specification "width") to the spread of the process values, as measured by 6 process standard deviation units
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