Suppose a researcher is interested in the relationship between periodontal disea

Question

Suppose a researcher is interested in the relationship between periodontal disease and a number of negative health outcomes. One outcome of particular interest to the researcher is hypertension (assume that this population has an average systolic blood pressure of 140 mmHg). Suppose a team gathers a simple random sample of 348 participants with periodontal disease, and finds the sample average systolic blood pressure to be 157 mmHg. Use an = 0.05 and = 16 mmHg.

Construct a 95% confidence interval for the sample mean. Provide an accurate interpretation of your interval.

Explanation / Answer

We will use T distribution because population standard deviation is unknown and degree of freedom = 348-1 = 347

Margin of error = (1.9668*16)/Sqrt(348) = 1.6869

95% Interval

(157-1.6869, 157+1.6869)

= (155.3131, 158.6869)

So, 95% Interval is  (155.3131, 158.6869)

Interpretation: We are 95% Confident that Population mean (Average Systolic pressure) will lies in this interval

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.