Determine how many standard deviations (z) the sample mean (xbar = 17), from a s

Question

Determine how many standard deviations (z) the sample mean (xbar = 17), from a sample (n) of 37, is from the population mean (mu = 9.1) for a large population, where the population standard deviation (sigma) is 6.5. Enter your response to two decimals (i.e. 0.12), as you would use to determine probabilities from the standard normal distribution table in the textbook.

QUESTION 9

Calculate the sample proportion (pbar, estimate of the population proportion) where 223 (x) exhibited the attribute/characteristic of interest in a sample of 2,860 (n). Enter your response to three decimals (i.e. 0.123).

QUESTION 10

Calculate the difference (absolute "positive" value) between the point estimate (pbar) and the parameter (p) where the proportion in the population for the outcome of interest is 0.49 (population parameter, p) and the number in a sample of 907 that are the outcome of interest is 395. Enter your response to two decimals (i.e. 0.12).

QUESTION 11

Calculate the standard deviation of the distribution of sample proportions (sigma pbar) where the proportion in the population exhibiting the attribute/characteristic of interest is 0.23 and the size for the samples is 550. Assume the population is very large. Enter your response to four decimals (i.e. 0.1234).

QUESTION 12

Calculate the standard deviation of the distribution of sample proportions (sigma pbar) where the proportion in the population exhibiting the attribute/characteristic of interest is 0.41, the size of the samples to be selected are 248, and the population size is 1,361. Enter your response to four decimals (i.e. 0.1234). (hint: use the finite population correction factor as n/N>.05)

QUESTION 13

Determine the probability of a sample proportion yielding a z value of 1.52 (standard deviations of the proportion) or less. Enter your response as a probability to four decimals (i.e. 0.1234). Use NORMSDIST function.

QUESTION 14

Determine the probability of a sample proportion being within plus or minus 0.02 (of the population parameter) where the population proportion is 0.57, the sample size is 884, and the population is very large. Enter your response as a probability to two decimals (i.e. 0.12).

Explanation / Answer

Question 8)

z = ( x bar – Mean ) / (sigma / sqrt(n))

= (17 – 9.1)/(6.5/sqrt(37))

= 7.39

Answer: 7.39

Question 9)

p bar = x / n

            = 223/2860

            = 0.078

Answer: 0.078

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