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Question 1 What is the sample size, n? ( i think this is 10) Question 2 What is

ID: 3261722 • Letter: Q

Question

Question 1

What is the sample size, n? ( i think this is 10)

Question 2

What is probability of a success, ?   Give in the form of a decimal.

Question 3

What is the average number of orange M&M’s? ( i think this is 2)

Question 4

What is the standard deviation of orange M&M’s?  Give solution to three decimal places.

Question 5

Find the probability of selecting five or fewer orange M&M’s out of a sample of ten.  Give solution to four decimal places.

Question 6

When sampling 10 M&M’s, what is the probability of getting exactly four that are orange?  Give solution to four decimal places.

Question 7

What is the probability that the number of orange M&M’s drawn out of ten is more than three, but less than nine?  Give solution to four decimal places.

Question 8

Find the probability of selecting more than 2 orange M&M’s out of a sample of ten.  Give solution to four decimal places.

Question 9

When sampling 10 M&M’s, what is the probability of getting five that are not orange?  Give solution to four decimal places.  

Color red orange yellow green blue brown total Avg Class Estimate 7 15 7 9 14 7 59 Percentage based on Class Estimate 12% 25% 12% 15% 24% 12% 100% Per M&M;'s Official 13% 20% 14% 16% 24% 13% 100%

Explanation / Answer

Answer to question# 1)

The sample size in this case is total of the average class estimate

We have total = 59

thus the sample size is 59

.

Answer to question# 2)

Probability of success depends on how is success defined. Suppose if success is defined as color "red"

Then Probability of success = 0.12 ( that is the 12% that is mentioned in the third column of the table above)

.

Answer to question# 3)

Average number of oranges M & M's is

20% of 59 = 0.2 *59 = 11.8 = 12

.

Answer to question# 4)

Since p = 0.2 , n = 59 ........[for M & M's]

Standard deviation = sqrt(n * p *(1-p))

Standard deviation = sqrt(59 * 0.2 * 0.8)

Standard deviation = sqrt(9.44)

Standard deviation = 3.0725

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