answer question circled 426 PART V From the Data at Hand to the World at Large 4
ID: 3260482 • Letter: A
Question
answer question circled
Explanation / Answer
a) X = -10, 0 or 40 for your winnings (or losses). The corresponding probabilities are:
P(40) = 1/6
P(0) = (5/6)(1/6) = 5/36
P(-10) = 1 - 1/6 - 5/36 = 25/36
b) E(X) = (-10)(25/36) + 0(5/36) + 40(1/6) = -5/18
E(X^2) = (100)(25/36) + 1600(1/6) = 3025 / 9
Var(X) = E(X^2) - [E(X)]^2 = 3025 / 9 - (-5/18)^2 = 108875 / 324
Std Dev. = sqrt [Var X] = 119043 / 6494 equal approximately 18.331
c) E(X) = (-10)(25/36) + 0(5/36) + 40(1/6) = -5/18
5 * E(X) = - 25/18
Std Dev. = 5 * 18.331 = 91.65
d) Probability that customer loses:
P(X < 0) = P{ z < [0 - (-5/18)] / [(119043 / 6494) / sqrt 100] } = P(z < 0.1515) = 0.560
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