GreenBeam Ltd. claims that its compact fluorescent bulbs average no more than 3.

Question

GreenBeam Ltd. claims that its compact fluorescent bulbs average no more than 3.24 mg of mercury. A sample of 25 bulbs shows a mean of 3.29 mg of mercury.

State the hypotheses for a right-tailed test, using GreenBeam’s claim as the null hypothesis about the mean.

Assuming a known standard deviation of 0.21 mg, calculate the z test statistic to test the manufacturer’s claim. (Round your answer to 2 decimal places.)

** Need help with this part

Find the p-value. (Round intermediate calculations to 2 decimal places. Round your answer to 4 decimal places.)

GreenBeam Ltd. claims that its compact fluorescent bulbs average no more than 3.24 mg of mercury. A sample of 25 bulbs shows a mean of 3.29 mg of mercury.

Explanation / Answer

a),H0: 3.24 mg vs. H1: > 3.24mg

b) ,given n = 25 standard deviation = 0.21 X^=3.59 a= 0.01

the value of the test statistic is Z = (x^ -mean) /(s /sqrt N)

Z= 3.29 - 3.24 / (0.21/sqrt25)

z= 0.05/ (0.21/5)

z = 0.05/0.042 = 1.19

c) alpha =0.01 Z a/2 = 0.01

from standard z table 99% c.i is 2.33

as Z less than i.e 1.19 less than 2.33 we will not reject hypothesis

so its noo

d) p value = 1 - Normsdist(1.19) =0.1170

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