A bag comtains 20 marbles: 5 yellow, 2 white, 3 blue, and 10 green. if 4 are sel
ID: 3259349 • Letter: A
Question
A bag comtains 20 marbles: 5 yellow, 2 white, 3 blue, and 10 green. if 4 are selected at random, find the probability that the that a) 2 are yellow, with replacement, b) 2 are yellow without replacement, c) all are green, with replacement, e) there is one of each color,with replacement, f) there is one of each color without replacement, g) both white are taken, with replacement, and h) both whites are taken, without replacement.
Explanation / Answer
A) P(2 are yellow, with replacement) = 4C2 x 5/20 x 5/20 x 15/20 x 15/20 = 0.2109
B) P(2 are yellow, withour replacement) = 4C2 x 5/20 x 4/19 x 15/18 x 14/17 = 0.2167
C) P(all are green, with replacement) = 10/20 x 10/20 x 10/20 x 10/20 = 0.0625
E) P(one of each color, with replacement) = 5/20 x 2/20 x 3/20 x 10/20 x 4! = 0.045
F) P(one of each color, without replacement) = 5/20 x 2/19 x 3/18 x 10/17 x 4! = 0.0619
G) P(both white are taken, with replacement) = 2/20 x 2/20 x 18/20 x 18/20 x 4C2 = 0.0486
H) P(both white are take, without replacement) = 2/20 x 1/19 x 18/18 x 17/17 x 4! = 0.0316
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