1. Inverse Normal Distribution X is normally distributed with a mean of 8.05 and

Question

1. Inverse Normal Distribution

X is normally distributed with a mean of 8.05 anda standard deviation of 1.40.

Find the value of x that solves P(X > x)= 0.30

A) -10.370

B) -9.667

C) -4.706

D) 4.548

E) 4.676

F) 5.977

G) 8.784

H) 11.169

I) 14.023

J) 18.307

2. Central Limit Theorem

X1, X2, ... ,X32 is a random sample from a distribution withmean = -1.24 and variance 2 = 1.80.

Find P(-1.28 < X -0.84).

A) 0.003

0.248

0.521

0.589

0.624

0.782

0.827

0.957

0.967

0.978

A) 0.003

B)

0.248

C)

0.521

D)

0.589

E)

0.624

F)

0.782

G)

0.827

H)

0.957

I)

0.967

J)

0.978

Explanation / Answer

1)P(x>x)=0.30

p(x<X)=0.70

x-8.05/1.40 =P(z=0.70)

=0.524399

x-8.05/1.40 =0.524399

x=8.7842

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