Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

In a test of weight loss programs, 148 subjects were divided such that 37 subjec

ID: 3257088 • Letter: I

Question

In a test of weight loss programs, 148 subjects were divided such that 37 subjects followed each of 4 diets. Each was weighed a year after starting the diet and the results are in the ANOVA table below. Use a 0.05 significance level to test the claim that the mean weight loss is the same for the different diets.

Should the null hypothesis that all the diets have the same mean weight loss be rejected?

A. No because the P-Value is less than the significance level.

B No because the P-Value is greater than the significance level.

C. Yes because the P-Value is greater than the significance level.

D. Yes because the P-Value is less than the significance level.

Source variastion ss df MS F P-value F Crit between groups 206.193 3 68.73101 2.0419 0.110656 2.667443 within groups 4847.086 144 33.66032 total 5053.279 147

Explanation / Answer

Question:

Should the null hypothesis that all the diets have the same mean weight loss be rejected?

Answer:

B. No because the P-value is greater than the significance level.

Explanation:

Null and Alternative Hypothesis:

Null Hypothesis (H0): All the population means are equal.

Alternative Hypothesis (H1): At least one of the population mean differs.

Level of significance = .05

Critical F = 2.667443

P-value = 0.110656

Here p value is greater than the level of significance; we fail to reject the null hypothesis.

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote