This Question: 1 pt This Quiz: 15 pts possible 8 of 15 (11 complete) An increase
ID: 3256932 • Letter: T
Question
This Question: 1 pt This Quiz: 15 pts possible 8 of 15 (11 complete) An increased number of colleges have been using online resources to research applicants. According to a study from last year, 34% of admissions officers indicated that they visited an applying student's social networking page. A random sample of 500 admissions officers was recently selected and it was found that 178 of them visit the social networking sites of students applying to their college. Using o -0.10, complete parts a and b below. a. Does this sample provide support for the hypothesis that the proportion of admissions officers who visit an applying students' social networking page has increased in the past year? Determine the null and alternative hypotheses. Choose the correct answer below. O B. Ho: 20.34 A. H p 30.34 H1: 0.34 H1: p 0.34 H1: p 0.34. H1: ps0.34 Determine the critical value(s) of the test statistic. (Use a comma to separate answers as needed. Round to two decimal places as needed.)Explanation / Answer
a) the null and alternate hypothesis for this study is
H0: p0= 0.34 versus
H0: p0>0.34 one tailed test
option a correct
this test is tested at a= 0.10 level of significance
the critical value at 0.1 level of siginficance is Za = 1.282
from standard normal table
the sample proportion p^ = x/ n = 178/500 =0.356
since np0 = 500*0.34=170>5
we use z test for hypothesis
z= p^-po / ( sqrt(po(1-po)/n))
= 0.356-0.34/(sqrt(0.34(1-0.34)/500))
=0.7552
the test stastic zp-=0.7552
here the valuclate d value is smaller than the tabulated value so
option c is correct do not reject h0 there is no sufficent evidence
b) p value for this test
here it is upper tailed test
p(z>0.7552) = 1-0.7734 = 0.2266
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.