The local lottery is found by randomly selecting 6 ping-pong balls from a contai
ID: 3254688 • Letter: T
Question
The local lottery is found by randomly selecting 6 ping-pong balls from a container in order without replacement. There are 30 ping pong balls in the container numbered 0 through 29. a) What is the probability you hold the winning ticket? b) How many tickets should you buy to give yourself a 1% chance of winning the lottery? A 10% chance? A 25% chance? A 50% chance? c) What is the probability all 6 numbers are even? At least one number is odd? d) what is the probability each number will be a single digit? What is the probability your 6-digit birthday will be the winning ticket? e) Complete parts (a) through (d) again under the assumption the order of the digits is irrelevant. How are your chances of winning affected? Better? Worse? Explain. f) How many ping pong balls are needed in the container to produce an (approximately) equal chance of winning if the order of the ping-pong balls is irrelevant?Explanation / Answer
Solving first 4 subparts as per CHegg policy
a) Probabibility of winning = 1/ 30C6=720/[30*29*28*27*26*25]
b) No. of tickets to gigive 1% chance of wiining = [30*29*28*27*26*25]/720/100=5938
c) Probability all 6 numbers are even = 15C6/30C6= 15*14*13*12*11*10/[30*29*28*27*26*25]=0.0084
d) Probability that each number is single digit = 10C6/30C6 = 10*9*8*7*6*5/[30*29*28*27*26*25]=0.0003
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