A. median and quartiles B. mean and quartiles C. median and standard deviation T

Question

A. median and quartiles
B. mean and quartiles
C. median and standard deviation

The five-number summary of scores on a test, in increasing order from the minimum to the maximum, is:

35 60 65 70 90

Based on this information

A. there are both suspected high and low outliers.
B. there are both suspected high and low outliers.

Consumer Reports often reviews current-model-year cars. The boxplots below can help us compare the 0 to 60 mph acceleration times (in seconds) of cars in several categories: small cars (4-cylinder engines), family sedans, large sedans, upscale sedans (all 6-cylinder engines), and luxury sedans (a mixture of 6- and 8-cylinder engines). The smaller the acceleration time, the faster the car accelerates. In which category was the car with the fastest acceleration (that is, the shortest acceleration time)?

A. Large
B. Small
C. Upscale

1. The histogram below shows the distribution of the annual hours of commuting delay per traveler for 46 small and medium urban areas (fewer than 1 million in population). Which measure of center and variability would be most appropriate to report for this distribution? 10 5 10 15 20 25 30 35 40 45 50 hours

Explanation / Answer

1.

Correct option:

A.    median and quartiles

EXPLANATION: Since it is highly skewed distribution, mean and standard deviation are influenced by outliers. Only median and quartiles are applicable.

5.

Inter Quartile Range = Q3 - Q1 = 70 - 60 = 10

Lower Inner Fence = Q1 - 1.5 IQR = 60 - (1.5 X 10) = 45

So, there is an outlier = 35 on Low Side

Lower Outler Fence = Q3 + 1.5 IQR = 70 + (1.5 X 10) = 85

So, there is an outlier = 90

There are both suspected high and low outliers.

6.

Correct option:

C. Upscale

7.

Coorect option:

the median must be between 1.3 and 2.2.

EXPLANATION:

Mean and mode cannot be identified in a boxplot.

Arranging numbers in ascending order, we get:

1.2,1.3,1.9,2.2,2.4

x is any number in between.

Total number including x = N = 6

So,

Median is (N+1)/2 th item.

So, we note that irrespective of value x , median must be between 1.3 and 2.2.

9.

Correct option:
A... boxplots show less detail

EXPLANATION:

Mean and mode cannot be identified in a boxplot.

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