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ID: 3252626 • Letter: Q

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Question 17

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Frequency Class

Observed Frequency

Less than 118

5

118 - 128

9

128 - 138

15

138 - 148

12

148 - 158

8

158 - 168

6

Greater than 168

5



State the appropriate null and alternative hypothesis.

Select one:

A. H0: The population has a Normal distribution with mean of 30. AND Ha: The population does not have a Normal distribution with a mean of 30.

B. H0: The population has a Normal distribution with mean of 150 and standard deviation of 30. AND Ha: The population does not have a Normal distribution with mean of 150 and standard deviation of 30

C. H0: The population dos not have a Normal distribution. AND Ha: The population has a Normal distribution.

D. H0: The population has a Normal distribution. AND Ha: The population does not have a Normal distribution.

Question 18

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<trheight="0">  

Frequency Class

Observed Frequency

Less than 118

5

118 - 128

9

128 - 138

15

138 - 148

12

148 - 158

8

158 - 168

6

Greater than 168

5

Select one:

A. 23.5568

B. 24.6880

C. 16.4580

D. 8.5860

Question 19

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<trheight="0">  

Frequency Class

Observed Frequency

Less than 118

5

118 - 128

9

128 - 138

15

138 - 148

12

148 - 158

8

158 - 168

6

Greater than 168

5

Select one:

A. 14.449

B. 11.143

C. 12.592

D. 9.488

Question 20

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A company that owns department stores advertised for one month on television and radio and in newspapers and spend the same amount of money on each of these three media. A random sample of 900 customers who visited this company s department stores during that month as a result of these promotional advertisements was asked which advertising medium was most effective in getting each of them to visit the stores. The responses of these customers are recorded in the following table.

Company director would like to test the null hypothesis that these three media sources have the same promotional impact on customers. What is the appropriate test?

Select one:

A. Test of Independence

B. Goodness of fit test - Multinomial Population

C. Goodness of fit test - Poisson distribution with expected value of 3

D. Goodness of fit test - Normal distribution with mean of 3 and standard deviation of 1

Frequency Class

Observed Frequency

Less than 118

5

118 - 128

9

128 - 138

15

138 - 148

12

148 - 158

8

158 - 168

6

Greater than 168

5

Explanation / Answer

Ans:17) Option D is correct.
H0: The population has a Normal distribution. AND Ha: The population does not have a Normal distribution.

(Ref:

Null hypothesis: In Chi-Square goodness of fit test, the null hypothesis assumes that there is no significant difference between the observed and the expected value.

Alternative hypothesis: In Chi-Square goodness of fit test, the alternative hypothesis assumes that there is a significant difference between the observed and the expected value.)

19)Critical chi square value for degree of freedom=7-3=4(for normal distribution df=n-3) and significance level=0.05 is

9.488

Hence,option D is correct.

20) Option A is correct.

Chi square test of independence.

18)

Frequency Class Observed Frequency (O-E)^2/E Less than 118 5 1.487153 118 - 128 9 0.021575 128 - 138 15 4.824376 138 - 148 12 1.3728 148 - 158 8 0.037911 158 - 168 6 0.7707 Greater than 168 5 1.487153 test statistic 10.00167
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