A simple random sample of 58 adults is obtained from a normally distributed popu

Question

A simple random sample of 58 adults is obtained from a normally distributed population, and each person's red blood cell count (in cells per microliter) is measured. The sample mean is 5.21 and the sample standard deviation is 0.53. Use a 0.05 significance level and the given calculator display to test the claim that the sample is from a population with a mean less than 54, which is a value often used for the upper limit of the range of normal values. What do the results suggest about the sample group? A. H_0: mu = 5.4 H_1: mu > 5.4 B. H_0: mu = 5.4 H_1: mu

Explanation / Answer

Solution:-

(B) Ho : mu = 5.4
H1 : mu < 5.4

Test statistic,
SE = s/sqrt(n) = 0.53 / sqrt(58) = 0.0696
DF = n - 1 = 58 - 1 = 57
t = (xbar - mu) / SE
= (5.21 - 5.4) / 0.0696
= -2.730

Corresponding P-value for t = -2.73 is
The P-Value is .004205 or 0.0042
The result is significant at p < .05.

Conclusion. Since the P-value (0.0042) is smaller than the significance level (0.05), we can reject the null hypothesis.

Reject Ho : (B)

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