to help plan the number of meals to be prepared in a college cafeteria, a survey
ID: 3248643 • Letter: T
Question
to help plan the number of meals to be prepared in a college cafeteria, a survey was conducted and the following data was obtained 129 students ate breakfast, 179 students ate lunch,275 students ate dinner,67 students ate breakfast and lunch,112 students ate breakfast and dinner, 90 students ate lunch and dinner, and 57 students ate all three meals. how many of the students ate only dinner ? what is the probability that a randomly selected student ate lunch or dinner or both? given that a randomly selected student ate breakfast, what is the probability that the student also ate lunch?
Explanation / Answer
total number of students =129+179+275-67-112-90+57=371
number of students ate only dinner =(275-112-90+57)/371=0.3504
probability that a randomly selected student ate lunch or dinner or both=(179+275-90)/371=0.981132
given that a randomly selected student ate breakfast, what is the probability that the student also ate lunch
=67/129=0.51938
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