A researcher asks college students to evaluate three new cell phone designs. How

Question

A researcher asks college students to evaluate three new cell phone designs. However, the researches suspects that college students may have criteria that a-e different from those used by rider adults. To test this hypothesis, the researcher performs a study using a sample of n = 60 older adults in addMon to a sample of n = 60 students. The distribution of preferences is as follows. Do the data indicate that the distribution of preferences for older adults is significantly different from the distribution for college students? Test with alpha = .05. (Use two decimal places.) Find the expected frequencies and compute the chi-square statistic. (Use two decimal places for f_N and X^2, three for each (f_a - f_N)2/f_N.) X^2 critical value = X^2 = Conclusion: Reject the null hypothesis; there is no significant difference between the preferences of students and those of older adults. Reject the null hypothesis; there is a significant difference between the preferences & students and those of older adults. Fail to reject the null hypothesis; there is a significant difference between the preferences of students and those of older adults. Fail to reject the null hypothesis; there is no significant difference between the preferences of students and those of older adults.

Explanation / Answer

from above given table:

hence

chi square critical value =5.9915

X2 =7.9352

reject the null hypothesis there is a significant differnce............

Observed O design 1 design 2 design 3 Total student 27 20 13 60 older adult 21 34 5 60 Total 48 54 18 120 Expected E=rowtotal*column total/grand total design 1 design 2 design 3 Total student 24.000 27.000 9.000 60 older adult 24.000 27.000 9.000 60 Total 48 54 18 120 chi square =(O-E)^2/E design 1 design 2 design 3 Total student 0.375 1.8148 1.7778 3.968 older adult 0.375 1.815 1.778 3.968 Total 0.750 3.630 3.556 7.9352

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