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Urgent please ... 1) A retailer knows that in a box of twelve light bulbs there

ID: 3248443 • Letter: U

Question

Urgent please ... 1) A retailer knows that in a box of twelve light bulbs there are four that will not work , he watches as a customer insists in removing and testing three. What is the probability that only one of the three tested fail to work ? 2) if it is estimated that a football player scores 85% of his free kicks. What is the probability that he scores more than 4 of his next free kicks ? 3) in a pack of twelve television tubes three are said to be defective. If a random sample of four is drawn from the pack with replacement what is the probability that - atleast 4 is defective and at most 2 is defective? Thank you Urgent please ... 1) A retailer knows that in a box of twelve light bulbs there are four that will not work , he watches as a customer insists in removing and testing three. What is the probability that only one of the three tested fail to work ? 2) if it is estimated that a football player scores 85% of his free kicks. What is the probability that he scores more than 4 of his next free kicks ? 3) in a pack of twelve television tubes three are said to be defective. If a random sample of four is drawn from the pack with replacement what is the probability that - atleast 4 is defective and at most 2 is defective? Thank you 2) if it is estimated that a football player scores 85% of his free kicks. What is the probability that he scores more than 4 of his next free kicks ? 3) in a pack of twelve television tubes three are said to be defective. If a random sample of four is drawn from the pack with replacement what is the probability that - atleast 4 is defective and at most 2 is defective? Thank you

Explanation / Answer

(1) N = 12, n = 3, k = 4, x = 1

P(x: N, n, k) = C(k, x) * C(N - k, n - x) / C(N, n)

P(1: 12, 3, 4) = C(4, 1) * C(12 - 4, 3 - 1) / C(12, 3)  = 0.51

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