Question
b) please, explain each step
Homework: Section 7.3 Score: 0.25 of 1 pt &7.3.15 Save 12 of 18 (13 complete) HW Score: 68.06%, 12.25 of 18 pts Question Help In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes in their levels of LDL cholesterol (in mg/dL) have a mean of 5.3 and a standard deviation of 16.4. Complete parts (a) and (b) below sabletm Chol ar a. What is the best point estimate of the population mean net change in LDL cholesterol after the garlic treatment? The best point estimate is 5.3 mg/dL. (Type an integer or a decimal.) b. Construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment, what does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? What is the confidence interval estimate of the population mean ? mg/dL
Explanation / Answer
Sample size n=42, sample mean xbar=5.3 and sample standard deviation s=16.4
Degree of freedom =n-1=42-1=41
Critical t at 10% level =1.6829
So confidence interval = xbar-1.6829*s/sqrt(n) , xbar+1.6829*s/sqrt(n)
=5.3-1.6829*16.4/sqrt(42) , 5.3-1.6829*16.4/sqrt(42)
=(1.04 9.56)
