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2 f 1 26 complete his Test : 188 pts possible Question Help The data show the nu

ID: 3246129 • Letter: 2

Question

2 f 1 26 complete his Test : 188 pts possible Question Help The data show the number of hours of television watched per day by a sample of 28 people. Use technology and the box-and-whisker plot below to answer parts (a), (b), and (c) below. 1 11 2 9 2 9 7 1 6 7 Click the icon to view the box-and-whisker plot. a. About 75% of the people watched no more than how many hours of television per day? About 75% of the people watched no more than [ ] hours of television per day. (Type an integer or a decimal. Do not round.) b. What percent of the people watched more than 5.5 hours of television per day? Choose the correct answer below. 0 A. About 60% of the people watched more than 5.5 hours of television per day. 0 B. About 25% of the people watched more than 55 hours of television per day. ° C. About 75% of the people watched more than 5.5 hours of television per day. 0 D. About 50% of the people watched more than 55 hours of television per day. ot onenersn from the sample. What is the likelihood that the person watched less than

Explanation / Answer

Given data

1 , 11 , 2 , 9 2, 9 , 7 , 1 , 6 , 7

5 , 3 , 1 , 7 ,4 , 6 , 1, ,0 , 7

9 , 8 , 7 , 3 , 5 , 5 , 9 , 9 , 3

About 75 % of the people watched no more than how many hours ?

about 75% means atleast 21 iems out of 28 must be no more than that hour

By observing the data there are only five 9's one 8 and one 11 that are greater than 7 i.e we have a total of 21 items less than 7 so

About 75 % of the people watched no more than is 7 hours

b)what % of people watched more than 5.5 hous ?

BY observing the data it is clear that there are

two 6 's

five 7 's

one 8

five 9's

one 11

more than 5.5 the total number is 14

calculating % = (14/28)* 100

= 50%

hence option D is correct

C)

there are 7 members that watch less than 2.5 hours

total number = 28

maximum liklihood = 7C1/28C1

=7/28

=0.25

we have to calculate in % the % is 0.25*100=25%

hence option A is correct

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