Suppose that a customer is purchasing a car. He conducts an experiment in which

Question

Suppose that a customer is purchasing a car. He conducts an experiment in which he puts 10 gallons of gas in the car and drives. It until it runs out or gas. He conducts this experiment 15 times on each car and records the number of miles driven. Describe each data set that is determine the shape, center, and spread Sample mean for Car 1 x = mi/10gal (Type an integer or decimal rounded to one decimal place as needed.) Sample mean for Car 2 x = mi/10 gal (Type an integer or decimal rounded to one decimal place as needed.) Median for Car 1 M = mi/10gal (Type an integer or decimal rounded to one decimal place as needed.) Median for Car 2 M = mi/10 gal (Type an integer or decimal rounded to one decimal place as needed.) Range for Car 1 R = mi/10 gal (Type an integer or decimal rounded to one decimal place as needed.) Range for Car 2 R = mi/10gal (Type an integer or decimal rounded to one decimal place as needed.) Sample standard deviation for Car 1 S = mi/10gal (Type an integer or decimal rounded to one decimal place as needed) Sample standard deviation for Car 2 S = mi/10 gal (Type an integer or decimal rounded to one decimal place as needed) Which car would the customer buy and why? A. Car 1, because it has a lower mean gas mileage B. Car 1, because it has a lower sample standard deviation, hence more predictable gas mileage. C. Car 2, because it has a larger range of gas mileage D. There is very little difference between the two cars.

Explanation / Answer

Sample mean for Car 1 = 250.2 mi/10 gal. (Ans).

Sample mean for Car 2 = 245.1 mi/10 gal. (Ans).

Median for Car 1 = 249 mi /10 gal. (Ans).

Median for Car 2 = 246 mi/10 gal. (Ans).

Range for Car 1 = 89 mi/10 gal. (Ans).

Range for Car 2 = 149 mi/10 gal. (Ans).

Sample standard deviation for Car 1 = 25.4 mi/10 gal. (Ans).

Sample standard deviation for Car 2 = 42.5 mi/10 gal. (Ans).

The customer will buy Car 1 because it has a lower sample standard deviation, hence more predictable gas mileage. So Option (B) is the correct choice. (Ans).

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