In a past election, the voter turnout was 71%.In a survey,1135 subjects were ask
ID: 3244791 • Letter: I
Question
In a past election, the voter turnout was 71%.In a survey,1135 subjects were asked if they voted in the election.
a. Find the mean and standard deviation for the numbers of voters in groups of 1135.
b. In the survey of 1135 people, 843 said that they voted in the election. Is this result consistent with the turnout, or is this result unlikely to occur with a turnout of 71%?Why or why not?
c. Based on these results, does it appear that accurate voting results can be obtained by asking voters how they acted?
Explanation / Answer
a)
mean = np = 1135 * 71% = 805.85
standard deviation = sqrt(npq) = sqrt(1135 * 0.71 * 0.29) = 15.29
b)
mean + 2 * standard deviation = 805.85 + 2 * 15.29 = 836.43
since 843 is greater than 836.43 , it is not consistent
c)
No, it cant be
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