1. Confidence Interval of a Sample Mean (population Standard Deviation (sigma) i

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1. Confidence Interval of a Sample Mean (population Standard Deviation (sigma) is known) Zombies primary food source is brains and spinal cords a diet high in protein and low in carbohydrates, a form of low carb diet. Serum cholesterol levels are measured in 25 randomly selected adult zombies. The mean of the sample is found to be 151.4 the population SD (sigma) for zombies is assumed to be the same as for living humans, 38 mg/dl. a.Calculate the Standard Error for Zombie cholesterol for sample size 25 and known population sigma b. Calculate the lower value for the 95% CI for the mean cholesterol level for all Zombies c.Calculate the upper value for the 95% CI for the mean cholesterol level for all Zombies. D Calculate the lower value for the 90% CI for the mean cholesterol level for all Zombies E . Calculate the upper value for the 90% CI for the mean cholesterol level for all Zombies. F. Calculate the lower value for the 99% CI for the mean cholesterol level for all Zombies G. Calculate the upper value for the 99% CI for the mean cholesterol level for all Zombies. H. Repeat the study above without assuming the population SD for Zombie cholesterol is not known. Sample Mean = 151.4 mg/dl Sample Standard Deviation = 38 mg/dl. Sample Size = 25 Calculate the Standard Error for Zombie cholesterol sample size 25 and unknown population sigma Hint: You’ll need the t value for degrees of freedom = 24 to calculate SE and the CI I Calculate the lower value for the 95% CI for the mean cholesterol level for all Zombies when the population standard deviation is not known and it estimated by the SD of the sample

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Answer:

Confidence Interval of a Sample Mean (population Standard Deviation (sigma) is known) Zombies primary food source is brains and spinal cords a diet high in protein and low in carbohydrates, a form of low carb diet. Serum cholesterol levels are measured in 25 randomly selected adult zombies. The mean of the sample is found to be 151.4 the population SD (sigma) for zombies is assumed to be the same as for living humans, 38 mg/dl.

a.Calculate the Standard Error for Zombie cholesterol for sample size 25 and known population sigma

standard error = 38/sqrt(25) =7.6

b. Calculate the lower value for the 95% CI for the mean cholesterol level for all Zombies

z value for 95% =1.96

lower limit = 151.4-1.96*7.6 =136.50

c.Calculate the upper value for the 95% CI for the mean cholesterol level for all Zombies.

upper limit = 151.4+1.96*7.6 =166.30

D Calculate the lower value for the 90% CI for the mean cholesterol level for all Zombies

z value for 90% =1.645

lower limit = 151.4-1.645*7.6 =138.90

E . Calculate the upper value for the 90% CI for the mean cholesterol level for all Zombies.

upper limit = 151.4+1.645*7.6 =163.90

F. Calculate the lower value for the 99% CI for the mean cholesterol level for all Zombies

z value for 99% =2.576

lower limit = 151.4-2.576*7.6 =131.82

G. Calculate the upper value for the 99% CI for the mean cholesterol level for all Zombies.

upper limit = 151.4+2.576*7.6 =170.98

H. Repeat the study above without assuming the population SD for Zombie cholesterol is not known. Sample Mean = 151.4 mg/dl Sample Standard Deviation = 38 mg/dl. Sample Size = 25 Calculate the Standard Error for Zombie cholesterol sample size 25 and unknown population sigma Hint: You’ll need the t value for degrees of freedom = 24 to calculate SE and the CI I Calculate the lower value for the 95% CI for the mean cholesterol level for all Zombies when the population standard deviation is not known and it estimated by the SD of the sample

t value for degrees of freedom = 24 =2.064

standard error = 38/sqrt(25) =7.6

95% CI for the mean cholesterol level

lower limit = 151.4-2.064*7.6 =135.71

upper limit = 151.4+2.064*7.6 =167.09

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