54C09 centonw athx.ccmi Quiz Week 2 Quiz CH 4, 5, & 6 This Question factured by

Question

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Explanation / Answer

Solution:

Set up a 2*2 contigency table to evaluate the probability of a warranty-related repair.

0.06

a) Compute the probability that a new car selected at random needs a warranty repair
P(W) = 0.06
b) Compute the probability a new car selected at random needs a warranty repair and was manufactured by a domestic company
P(WD) = 0.033
c) Compute the probability a new car selected at random needs a warranty repair or manufactured by a domestic company.
P(WD) = P(W) + P(D) -P(WD)
= 0.06 + 0.670 -0.033
= 0.697
d) Compute the probability that a new card selected random needs a warranty repair or was made by aforeign company.
P(WF) = P(W) + P(F) -P(WF)
= 0.06 + 0.330 -0.027
= 0.363

Repair Needs Domestic(D) Foreign(F) Total Yes(W) 0.033   0.027

0.06

No(W') 0.637 0.303 0.94 Total 0.670 0.330 1.00

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