A survey of 1, 659 randomly selected adults showed that 568 of them have heard o

Question

A survey of 1, 659 randomly selected adults showed that 568 of them have heard of a new electronic reader The accompanying technology display claimthat38% of adults have heard of the new electronic Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). a. Is the test two-tailed, left-tailed, or right-tailed? Left tailed test Right tailed test Two-tailed tests b What is the test statistic? z = (Round to two decimal places as needed.) c What is the P-value? P-value = (Round to four decimal places as needed.) d. What is the null hypothesis and what do you conclude about it? Identify the null hypothesis. A H_0: p notequalto 0.38 B. H_0: p = 0.38 C. H_0: p 0.38 Choose the correct answer below A Reject the null hypothesis because the P-value is greater than the significance level alpha. B. Reject the null hypothesis because the P-value is less than or equal to the significance level alpha. C. Fall to reject the null hypothesis because the P-value is less than or equal to the significance level alpha D Fall to reject the null hypothesis because the P-value is greater than the significance level alpha e What is the final conclusion? A There is not sufficient evidence to warrant rejection of the claim that 38% of adults have heard of the new electronic reader. B. There is sufficient evidence to support the claim that 38% of adults have heard of the new electronic reader.

Explanation / Answer

a) it is two tailed test

b)test stat z=-3.1573

c)p value =0.0016

d) option B Ho: p=0.38

option B reject the null hypothesis...........

e) there is sufficient evidence to reject the claim that 38 % of adults heard.........

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.