Pad 23:58 Ims.rmit.edu.au Section C Answer on the multiple choice sheet Below is
ID: 3239980 • Letter: P
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Pad 23:58 Ims.rmit.edu.au Section C Answer on the multiple choice sheet Below is Excel output from a regression analysis to predict yriest nesul) from r (hours watching Ty homs), and x20studying hard-study horns) and x, eating chocolate (by the block) (chocolare) a. What is the equation of the regression model? b. Interpret the regression line? Statistics Multiple r 0912205 0,893392 Adjusted r Square Standard Emor 952.1605 Observations ANOVA MS Signifi vance F 32E+08 43977657 48.48745 .21E 07 14 2697866 906990.4 Total 17 .45EH08 Lower 95% Upper 95% Standard Error 529062 025.9 0.141246 0.889688 rIOT v hours) -137002 8.786907 -1.55916 0.141272 5.7 -11.7 12 (study hours) 1163776 .247247 9.330762 2.19E 07 0.63 2.63 (chocolate) 0.2 55 a From this formula, it would be true to say A. Increases to all of the variables (TV hours) (Study hours) and (chocolate) will increase Test result B. Increases to all of the variables TV hours and Chocolate will decrease test result C. Increases to the (Study hours) variable will increase the test result D. Both B and Care comect In this data analysis the Sum of the Square of Emors (SSE)is A, 952.3605 C. 36.84429 D. 12697866 c. If we examine the F value and given the critical value F a18.2 2.40 we can conclude A. None of the independent variables are significant at predicting Test result B. All of the independent variables are significant at predicting test result C. At least one of the independent variables are significant at predicting Test result D. 0.01Explanation / Answer
a) test result = 52.9062 - 13.7002 * TV Hours + 11.63776* Study hours - 10.2 * Chocolate
b)
a. D)
b. D)
c. C)
d. C)
e. D)
f. D)
g. D)
i. D)
2. a) Simple linear regression line
average points per game= 2.432821 + 0.04814 * Attempts
b) The estimated average points per game is 2.432821 when total number of attempts is 0
and the estimated average points per game will increase 0.04814 unit for a unit increase in the total number of attempts.
c) 74.3578% of variation in average points per game can be explained by the above regression equation.
d) Standard error of the regression having a value of 3.696478 is quite large, so the regression equation is not good enough.
e) For testing the slope of the regression model, we get p-value = 0 < 0.05, so at 5% level of significance, we can conclude that the slope has significant effect to predict the average points per game.
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