c Search eyplus.com/edugen/student/mainfr.uni ent FULL SCREEN BACK Using the sam

Question

c Search eyplus.com/edugen/student/mainfr.uni ent FULL SCREEN BACK Using the same table provided above: Retirement Benefits Have Yes T No Men 250 100 125 25 Women suppose one employee is selected at random from these 500 employees. Compute the folding probabilities. Provide your answers correct up to 2 decimal places. (a) The probability of the intersection of events "man" and "yes" (b) The probability of the intersection of events "no" and "woman (c) The probability of the union of events "man" or "no" click if you would like to show work for this question: Open Show Work By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor, licy I 2000-2017 yohn Wiley & Sons, Inc. All Rights Reserved. A Division of John Wiley & Sons, Inc,

Explanation / Answer

a) the probability of intersection of events 'man' and 'yes' = n(man and yes)/total employee = 250/500 = 0.5 (ans)

b) the probability of intersection of events 'woman' and 'no' = n(woman and no)/total employee = 25/500 = 0.05 (ans)

c) Probability of union of 'men' or 'no' = {n(men) + n(no) - n(men and no)}/Total employee

now, total number of men = n(men and yes)+ n(men and no) = 250+100 = 350 =n(men)

Similarly, total number of 'no' = n(no and men)+n(no and women) = 100+25 = 125 =n(no)

and n(men and no) = 100

So n(men or no) = 350+125-100= 375

So the probability = 375/500 = 0.75 (ans)

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