Find the probability that: A.) someone plays three times and doesn\'t win any ti

Question

Find the probability that: A.) someone plays three times and doesn't win any tickets Your probability skills are known far and wide, at least amongst your friends. You have recently "volunteered" to help with a fundraiser at a local junior high school. The fundraiser has planned a game where a player can win tickets based on a random trial. The game works like this: A player rolls a die with 10 sides. If the number is odd, the player loses. If the number is a 10, jackpotl The player wins 20 tickets. If the number on the die is 2, 4, 6, or 8, the player flips a coin. If the coin comes up Heads, the player wins the number of tickets on the die. If the coin comes up Tails, the player loses. Tickets can be exchanged for prizes, where each ticket is worth about 10 cents. (For example, a prize worth a dollar costs 10 tickets, a prize worth szo costs 200 tickets, and so on.) 1. (8 pts) create a probability model for this game. (List each outcome with its probability.) odd 0 no 0.05 (4/ loss

Explanation / Answer

(a)

Since, the outcome of 3 chances are independent of each-other. So,

Probability that someone plays three times and doesn't win any tickets

= (0.50+0.05+0.05+0.05+0.05)3

= (0.7)3

= 0.343

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(b)

Probability that someone plays twice and wins tickets on one of the plays  

= (Probability that he won in 1st chance and lost in 2nd + Probability that he lost in 1st and won in 2nd)

= (0.3*0.7) + (0.7*0.3)

= 0.21 + 0.21

= 0.42

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