The table to the right shows the number of female students who played on a sport

Question

The table to the right shows the number of female students who played on a sports team in grades 9 through 12 for a random sample of 6 high schools in state. At alpha = 0.01, can you reject the claim that the mean numbers of female students who played on a sports team are equal for all grades? Perform a one-way ANOVA test by completing parts a through d. Assume that each sample is drawn from a normal population, that the samples are independent of each other, and that the populations have the same variances. A. H_0: mu_1 = mu_2 = mu_3 = mu_4(claim) H_a: Al least one mean is different from the others. B. H_0: mu_1 = mu_2 = mu_3 = mu_4= mu_5 = mu_6 H_a: Al least one mean is different from the others. (claim) C. H_0: At least one mean is different from the others. (claim) H_a: mu_1 = mu_2 = mu_3 = mu_4= mu_5 D. H_0: mu_1 = mu_2 = mu_3 = mu_4 H_a: A least one mean is different from the others. (claim) (b) Identity the degrees of freedom for the numerator and for the denominator, determine the critical value, and determine the rejection region. The degrees of freedom for the numerator, f.f_N is 3, and the degrees of freedom for the denominator, d. f_D is 20. The critical value is F_0 = 4.94 (Round to two decimal places as needed.) The rejection region is F > 4. 94 (Round to two decimal places as needed) (c) Calculate the test statistic. (Round to three decimal places as needed.)

Explanation / Answer

(a) is Option A

(b) df numerator = c-1 = 4-1 = 3, df denominator = N-c = 24-4 = 20

Fcritical at 0.01,3,20 = 4.938 = 4.94(approximately)

The rejection region F>4.94

(c) The tables below give the value of the F stat

F = 0.057

Mean(x bar) 81 76.67 76.67 80 SD 22.95212 22.82689 23.07957 23.09978 Variance 526.80 521.07 532.67 533.60 n 6 6 6 6 columns 4

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.