Answer the kao ing questions about probabilities. the Baltimore Beltway and Are

Question

Answer the kao ing questions about probabilities. the Baltimore Beltway and Are the two eventa indevendnt you explain this relatiomaip (real world (e) The probability of Evesut A The peobalilury of Evear A and B at t 3 o events are indepeadent what is the probability ul Exeat B? (d) he probability of an accident on a partieulur high is 4 and the peababaty of an and there beiug ven that it rains is 6. What is the probability of it raining (e) if the probability that a particular batter will hit a homerun ia a game is 2 and the probability tdner is If the probahility of hittiag a homerua a game that he will face a right handed pit heir being a right handed pitcher is 15 what the probability draw frue this free hat there will be a right handed pitcher? What coerclusion would you moee info if needed)? to make EDUCATED gurmani to

Explanation / Answer

a)

If events A and B are independent then folloiwng must be true:

P(A and B)= P(A)P(B) = 0.2*0.4 = 0.08

But it is not equal to given probability P(A and B) = 0.1. So given statement is false.

b)

Given information:

P(accident on Beltimore Beltway and accident on DC highway) = 0.6

P(accident on Beltimore Beltway) = 0.7

P(accident on DC highway) = 0.8

If above two events are independent then folloiwng must be true

P(accident on Beltimore Beltway)P(accident on DC highway)=0.7*0.8 = 0.56

But it is not equal to P(accident on Beltimore Beltway and accident on DC highway) = 0.6.

Hence, events are not independent.

c)

P(A) = 0.4, P(A and B) = 0.3

Since A and B are independent so P(A and B)=P(A)P(B)

So P(B) = P(A and B) / P(A) = 0.3/0.4 = 0.75

d)

The required probability is

P(A and B) = P(A)P(B) = 0.4*0.6 = 0.24

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.