Fifty fifth-grace students from each of four city schools were given a standardi

Question

Fifty fifth-grace students from each of four city schools were given a standardized fifth-grade reading test. After grading, each student was rated as satisfactory or not satisfactory in reading ability, with the following results: Is there sufficient evidence to indicate that the percentage of fifth-grade students with an unsatisfactory reading ability varies from school to school? Use 1% level of significance level. Solution: H_0: p1 = p2 = p3 = p4 = p H_1: At least one proportion differs from at least one another. Test statistics: [a] Degree of freedom: [b] Critical value: [c] Therefore, we [d], reject the null hypothesis that reading ability for the fifth-grades as measured by this test does not vary from school to school.

Explanation / Answer

The statistical software output for this problem is:

Chi-Square goodness-of-fit results:
Observed: Not Satisfactory
Expected: All cells in equal proportion

Hence,

Test statistics = 3.33

Degree of Freedom = 3

For 3 degrees of freedom and 1% level of significance, Critical Value = 11.345

Therefore,

We do not reject the null hypothesis.

N DF Chi-Square P-value 36 3 3.3333333 0.343

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.