A found that out Probability that are underinsured. were underinsured If 5bouses

Question

A found that out Probability that are underinsured. were underinsured If 5bouses are Section find the selected from the 9 houses, 2) Find the probability Ans(I) get all heads or all ails the third time on the sixth toss. that a person tosing three coins will either for Ans (2) (3) The probability of a defective telephone in a large ofice building is0.3. a sample of7 selected, find there are exactly 4 defective telephone (4) In a music store, a manager found that the probabilities that a person buys 0, I. or 2 or more CDs are 0.2. 0.7 and 0. respectively. If six customers enter the store, find the probability that one won't buy any CDs, three will buy and two buy two or more CDs? (5 Ans(4). lf the probability is 0.07 that a certain kind of device will show excessive drift, what is the probability that The sixth device will be the first to show excessive drift? Ans.(

Explanation / Answer

1 Question at a time mate!

Here' the answer to the 1st question:

1) 4 out of 9 are uninsured.

So, the probability to be uninsured
= p = 4/9 = .44

We apply binomial distribution to solve the problem:

So, if 5 is selected from 9, P(X=2) = 5C2(.44^2)(.56^3) = .34

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