If you roll five dice, the probability of getting two \"sixes\" and three non-si

Question

If you roll five dice, the probability of getting two "sixes" and three non-sixes is about a) 16% b) 25% c) 1.00 d) 1.50 Given that the mean IQ score is 100 end standard deviation is 16, the z score of a person with IQ=108 is a) 0.00 b) 0.50 c)1.00 d) 1.50 A temple with mean-35 it drawn from a normally distributed population with sigma = 1 The 99.7% confidence interval will be: a) 32-38 b) 33-38 c) 34-37 d) 28-38 A population has StDev sigma-6. Samples of size n-9 are chosen. The standard deviation of the sampling distribution of the means is: a) 2 b) 4 C)16 d) 64 Calculate P(4) (the probability of drawing 4 aces without replacement from a full deck of 52 cards). a) 1/13 b) 1/2,704 c) 1/28,561 d) 1/270,725

Explanation / Answer

1)

probability of getting six in die roll = 1/6

probability of getting non six in die roll = 5/6

probablity of getting two sixes and three non-sixes = (5C2)(1/6)2(5/6)3 = 0.1608

2)

mean = 100

standard deviation = 16

z score for IQ = 108 = (108-100)/16 = -8/16 = -0.5

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