(a) Measurements of a known quantity are taken and the quanitity is normally dis
ID: 3232155 • Letter: #
Question
(a) Measurements of a known quantity are taken and the quanitity is normally distributed with mean 0.05. We obtain 0.041, 0.064, 0.055, 0.046, 0.060. Estimate the variance of the distribution.
(b) Suppose we know that the variance is, in fact 5.0 x 10^-5 . What is the value of the chi squared for this set of measurements?
(c) What is the "p value" for this value of chi squared?
(d) Supposed the variance of the underlying Gaussian is known to be 5.0 x 10^-5 but we didn't know the mean beforehand. Under these circumstances, what p value would be obtained?
Explanation / Answer
Answer:
Data x
x-0.05
(x-mean)^2
0.041
-0.009
0.000081
0.064
0.014
0.000196
0.055
0.005
0.000025
0.046
-0.004
0.000016
0.06
0.01
1E-04
Total
0.000418
Variance =0.000418/4=0.000105
Chi square= 4*0.000105/0.00005 =8.4
P=0.078
data
count
5
mean
0.05320
sample standard deviation
0.00958
sample variance
0.00009
Chi square= 4*0.00009/0.00005 =7.2
P=0.1257
Data x
x-0.05
(x-mean)^2
0.041
-0.009
0.000081
0.064
0.014
0.000196
0.055
0.005
0.000025
0.046
-0.004
0.000016
0.06
0.01
1E-04
Total
0.000418
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