The Genetics & IVF Institute conducted a clinical trial of the XSORT method desi
ID: 3231428 • Letter: T
Question
The Genetics & IVF Institute conducted a clinical trial of the XSORT method designed to increase the probability of conceiving a girl. As of this writing, 945 babies were born to parents using the XSORT method, and 879 of them were girls. Use a 0.01 significance level to test the claim that the XSORT method is effective in increasing the likelihood that a baby will be a girl.
what is the test statistic that was given in this video? round off to 3 decimal places.
Explanation / Answer
H0 : p = p0 = 0.5
Ha : p > p0 = 0.5
N = 945
p = 879/945 = 0.93
standard error of sampling se0 = sqrt p0 (1- p0)/N] = sqrt [ 0.5 * 0.5/ 945] = 0.0162
Test Statistic
Z = (p -p0)/ se0 = (0.93 - 0.5)/ 0.0162 = 26.543
Zcritical for alpha = 0.01 is equal to 2.575
so Z > Zcritical so we can reject the null hypothesis and can say that XSORT method is effective in increasing the likelihood that a baby will be a girl.
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