A consumer organization estimates that over a 1-year period 15% of cars will nee

Question

A consumer organization estimates that over a 1-year period 15% of cars will need to be repaired once, 7% will need repairs twice, and 3% will require three or more repairs. What is the probability that a car chosen at random will need a) no repairs? b) no more than one repair C) some repairs? a) The probability that a car will require no repairs is. (Do not round.) b) The probability that a car will require no more than one repair is. (Do not round.) c) The probability that a car will require some repair is. (Do not round.)

Explanation / Answer

Percentage of cars which requires repair>

Percentage of cars which need two repair = 7%

Percentage of cars which need three or more repair = 3%

a) The probability that a car will require no repair is given as

1 - (0.15 + 0.07 + 0.03) = 1 - 0.25 = 0.75

b) The probability that a car will require no more than one repair is given as

P(No repair) + P(one repair) = 0.75 + 0.15 = 0.90

c) The probability that a car will require some repairs is given as

P(One repair) + P(Two repair) + P(three or more repair) = 0.15 + 0.07 + 0.03 = 0.25

Final Answers:

a) 0.75

b) 0.90

c) 0.25

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