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also,can you tell me when you reject for the z-test, please? Thank you Suppose B

ID: 3231286 • Letter: A

Question

also,can you tell me when you reject for the z-test, please? Thank you

Suppose Burger King has run a major advertising campaign the hopes of increasing monthly sales. To investigate the effectiveness of this campaign, Burger King randomly selected six restaurants and recorded the monthly sales before and after the advertising. The following data represents these sales figures in thousands of dollars. If Population 1 is defined as the advertising campaign and Population 2 is defined as sales before the advertising campaign, and using alpha = 0.05, the conclusion for this hypothesis test would be that because the test statistic is A) less than the critical value, we can conclude that the average restaurant sales per month after the advertising campaign are higher than the average restaurant sales per month before the advertising campaign. B) more than the critical value, we can conclude that the average restaurant sales per month after the advertising campaign are higher than the average restaurant sales per month before the advertising campaign. C) less than the critical value, we cannot conclude that the average restaurant sales per month after the advertising campaign are higher than the average restaurant sales per month before the advertising campaign. D) more than the critical value, we can conclude that the average restaurant sales per month after the advertising campaign are less than the average restaurant sales per month before the advertising campaign.

Explanation / Answer

Restaurant

After(X)

Before(Y)

di

di^2

(d-d^bar)2

1

123

107

16

256

81

2

122

110

12

144

25

3

145

143

2

4

25

4

156

168

-12

144

861

5

160

145

15

225

64

6

134

125

9

81

4

Total

840

798

42

854

560

d^bar =d /n = 42 /6 =7

standard deviation S2 = (d-dbar)2

                                  =560/6-1

                                    =112

                        S          =sqrt(112)

                                    =10.58

test statistic tcal= d^bar /(S/sqrt(n))

                        =7/ (10.58 /sqrt(6)

                        =1.621

tcal                    =1.621

df        =5

=0.05

critical value tc =t0.025,df=5 =2.571

tcal < tc , accept null hypothesis ( fail to reject Ho)

conclusion :

If Population 1 is defined as sales after the advertising campaign and Population 2 is defined as sales before the advertising campaign, and using ? = 0.05, the conclusion for this hypothesis test would be that because the test statistic is

less than the critical value, we cannot conclude that the average restaurant sales per month after the advertising campaign are higher than the average restaurant sales per month before the advertising campaign

option C is correct

Restaurant

After(X)

Before(Y)

di

di^2

(d-d^bar)2

1

123

107

16

256

81

2

122

110

12

144

25

3

145

143

2

4

25

4

156

168

-12

144

861

5

160

145

15

225

64

6

134

125

9

81

4

Total

840

798

42

854

560

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