Question
A sorste somm has an average peak heigh of 164 feet waves hiting the shore Buppoee that a storm progress wn a severe siam dana rating Let us say Suppose you donot dying out. You iormdass rating what would you use for he aemane hypothesis tie height is dnement either up P.walue area on the let, right, or on both sides of the B:A is not equal to 164 feet, ne alue anna In on both of mean c A isless than 154teet the P-vaue area is on the arte mean Hi is not equal lo 164 feet, the P-waun e E HI:N is greater than 154Frnt he Pawalue area son sides at he mean stion 10 mal dwybuton a -25%. A tandom sanple at 24 Letz be a random wariable representing hvidend yield of Auntralan bank stocks. We may assame that 69i. Dathewe dala indicatethat he dvidend yirld Aerte dara statstovy grinant althe men level of sarinance? Based on your arawes wi you rejector to tigher than wi? a 0 reject ne full rypotheser A The P value b greater than the level of hua, we meject the nul data are statsscaay synteaft. Thes. Me tai to teject the rull ropothesis. c The P-wave greater han the level of rce and 50 data are stasssoal signscant. Thus, we reect the muampotress. ave Answer tion 11 he degrees or rhe sample sze s s2? When using the students tdsmbuson to test wtsl vaue do you use for
Explanation / Answer
10)
x = 8.07 , mean = 6 , s = 2.5 , n = 24
t = (x - mean) / ( s / sqrt(n))
= ( 8.07 -6)/( 2.5 / sqrt(24))
= 4.056
to find p value using t = 4.056 , df = 23
p va lue = .000245.
Answer i soption E)
11)
n = 32
so, df = n - 1 = 32 - 1 = 31
