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How many 5 digit numeric codes are possible if the first digit cannot be a four

ID: 3230935 • Letter: H

Question

How many 5 digit numeric codes are possible if the first digit cannot be a four and adjacent digits must be different. a. List the Sample space for possible Outcomes from spinning these two spinners. b. Give the probability of getting the same color on both spins c. Give the probability of getting a RED and a Yellow on the two spinners. (Each colored region is the same area within the circle) A group of 56 people was classified according to gender and age. a. What percent of the people are twenty or older 20? b. What percent of the people are less than 20 and female? c. What is the probability of randomly selecting a female from the population? d. What percent of people who are less than 20 are Male? e. What percent of males are 20 years old or Older? f) What is the probability of randomly selecting a female who is also less than 20? If a family is planning on having three children, what is the probability of having more girls than boys? In a game of chance, people will draw ducks out of a stream of water. The bottom of each duck indicates whether the person wins $1, $2, $3, $5, or $10. The probabilities for winning are given in the table below: Find the expected winning? If the game lost to play is it worth playing?

Explanation / Answer

Solving question 3,

First digit can be chosen in 8 different ways ( 1 to 9 excluding 4)

Second digit can thus be chosen in 9 different ways ( 0 to 9 ,excluding the chosen first digit)

THird digit can thus be chosen in 9 different ways(  0 to 9 ,excluding the chosen second digit)

Fourth digit can be chosen in 9 different ways((  0 to 9 ,excluding the chosen second digit)

Fifth digit can also be chosen in 9 different ways (((  0 to 9 ,excluding the chosen second digit)

Hence, no of combinations = 8*9*9*9*9 = 52488

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