The lumen output was determined for each of l = 3 different brands of lightbulbs
ID: 3230243 • Letter: T
Question
The lumen output was determined for each of l = 3 different brands of lightbulbs having the same wattage, with J = 10 bulbs of each brand tested. The sums of squares were computed as SSE = 4776 and SSTr = 596.4. State the hypotheses of interest (including word definitions of parameters). mu = sample average lumen output for brand/bulbs H_0: mu_1 = mu_2 = mu_3 H_a: all three are unequal mu = sample average lumen output for brand i bulbs H_0: mu_1 notequalto mu_2 notequalto mu_3 H_a: all three are equal mu = true average lumen output for brand i bulbs H_0: mu_1 notequalto mu_2 notequalto mu_3 H_a: at least two are equal mu = true average lumen output for brand i bulbs H_0: mu_1 = mu_2 = mu_3 H_a: at least two mu are unequal Use the F test of ANOVA (alpha = 0.05) to decide whether there are any differences in true average lumen outputs among the three brands for this type of bulb by obtaining as much information as possible about the P-value. f = What can be said about the P-value for the test? P-value > 0.100 0.050Explanation / Answer
1)for hypothesis last option D is correct
from above given information:
hence F=0.593
P value =1.0000 or P-value>0.100
Source of variation SS df MS F P value Between groups 2.000 596.4 0.003 0.593 1.00000 with in groups 27.000 4776 0.006 total 29.000 5372.4Related Questions
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