A digital communication system sends 1\'s and 0\'s in sequence with the probabil
ID: 3229999 • Letter: A
Question
A digital communication system sends 1's and 0's in sequence with the probability of transmitter the sending a 1 is 0.45. Errors are made in the communication channel, so the probability of receiving a 0 given that a l was sent is 0.03, and the probability of receiving a given that a 0 was sent is 0.02. a. Find the probability that a 0 was sent given that a 1 was received b. Find the probability that a t was sent given that a 0 was received. c. Find the total probability that a 1 was received d. Are the events that a 1 was transmitted and that a 0 was not received independent? Justify your answer.Explanation / Answer
probabilty of 1 receipt =P(1R)=P(1S)*P(1R|1S)+P(0S)*P(1R|0S)=0.45*0.97+0.55*0.02=0.4475
a) hence probabilty that 0 was sent given 1 was in receipt =P(0S|1R)=P(0S)*P(1R|0S)/P(1R)=0.55*0.02/0.4475
=0.0246
b)probabilty that 0 was erceived =P(0R)=1-P(1R)=1-0.4475=0.5525
hence probabilty that 1 was sent given 0 was received P(1S|0R)
=P(1S)*P(0R|1S)/P(0R)=0.45*0.03/0.5525=0.0244
c)probability 1 was received =P(1R)=0.4475
d)No as P(1S|0R) is not equal to P(1S)
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