Apartment Rental Fees: The data shown are the rental fees (in dollars) for two r
ID: 3229626 • Letter: A
Question
Apartment Rental Fees:
The data shown are the rental fees (in dollars) for two random samples of apartments in a large city.
At a=0.10, can it be concluded that the average rental fee for apartments in the east is greater than the average rental fee in the West?
Can it be concluded that the average rental fee for apartments in the east is greater than the average rental fee in the west?
EAST WEST
275 450 440 425 675 400 475 430 410 450
625 390 485 550 650 425 450 620 500 400
685 385 450 550 425 295 350 300 360 400
a). ( use minitab to run the A-D Tests of Normality) Report p Values, and Conclusions
b). State the null and alternative hypothesis, Report the test statistics, Report the degree of freedom, and the p value.
c). State your conclusion
495 390 540 445 420 525 400 310 375 750 410 550 499 500 550 390 795 554 450 370 389 350 150 530 350 385 395 425 500 550 375 690 325 350 799 38 400 450 365 425 475 295 350 485 625 375 360 425 400 475Explanation / Answer
Using minitab:
Two-Sample T-Test and CI: East, West
Two-sample T for East vs West
SE
N Mean StDev Mean
East 40 477 119 19
West 40 437 103 16
Difference = (East) - (West)
Estimate for difference: 40.1
95% lower bound for difference: -1.5
T-Test of difference = 0 (vs >): T-Value = 1.61 P-Value = 0.056 DF = 76
P-value < alpha we reject null hypothesis.
we have sufficient evidence to conclude mean 1 is greater than mean 2.
EAST Data:
P-value of AD test 0.163. which is greater than 0.1 so data is normal.
WEST Data: Anderson-Darling Normality Test: 2.09
P-value <0.005 using AD test we p-value is smaller so Data is not normal for West data
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