For this problem, carry at least four digits after the decimal in your calculati
ID: 3229029 • Letter: F
Question
For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.
A random sample of 5300 permanent dwellings on an entire reservation showed that 1557 were traditional hogans.
(a) Let p be the proportion of all permanent dwellings on the entire reservation that are traditional hogans. Find a point estimate for p. (Round your answer to four decimal places.)
(b) Find a 99% confidence interval for p. (Round your answer to three decimal places.)
Give a brief interpretation of the confidence interval.
1% of the confidence intervals created using this method would include the true proportion of traditional hogans.1% of all confidence intervals would include the true proportion of traditional hogans. 99% of the confidence intervals created using this method would include the true proportion of traditional hogans.99% of all confidence intervals would include the true proportion of traditional hogans.
(c) Do you think that np > 5 and nq > 5 are satisfied for this problem? Explain why this would be an important consideration.
No, the conditions are not satisfied. This is important because it allows us to say that p is approximately binomial.No, the conditions are not satisfied. This is important because it allows us to say that p is approximately normal. Yes, the conditions are satisfied. This is important because it allows us to say that p is approximately normal.Yes, the conditions are satisfied. This is important because it allows us to say that p is approximately binomial.
lower limit upper limitExplanation / Answer
a)p=1557/5300 =0.2938
std error =(p(1-p)/n)1/2 =0.0063
for 99% CI, z=2.5758
hence lower limit =p-z*std error =0.278
b)upper limit =p+z*std error =0.310
c)99% of the confidence intervals created using this method would include the true proportion of traditional hogans.
d)Yes, the conditions are satisfied. This is important because it allows us to say that p is approximately normal
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.